(1/(2k+8))+(1/2)=((k^2+k-20)/(k+4))

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Solution for (1/(2k+8))+(1/2)=((k^2+k-20)/(k+4)) equation:


D( k )

2*k+8 = 0

k+4 = 0

2*k+8 = 0

2*k+8 = 0

2*k+8 = 0 // - 8

2*k = -8 // : 2

k = -8/2

k = -4

k+4 = 0

k+4 = 0

k+4 = 0 // - 4

k = -4

k in (-oo:-4) U (-4:+oo)

1/(2*k+8)+1/2 = (k^2+k-20)/(k+4) // - (k^2+k-20)/(k+4)

1/(2*k+8)-((k^2+k-20)/(k+4))+1/2 = 0

1/(2*k+8)+(-1*(k^2+k-20))/(k+4)+1/2 = 0

(1*2*(k+4))/(2*(2*k+8)*(k+4))+(-1*2*(k^2+k-20)*(2*k+8))/(2*(2*k+8)*(k+4))+(1*(2*k+8)*(k+4))/(2*(2*k+8)*(k+4)) = 0

1*2*(k+4)-1*2*(k^2+k-20)*(2*k+8)+1*(2*k+8)*(k+4) = 0

2*k^2-4*k^3-20*k^2+66*k+16*k+32+328 = 0

82*k-4*k^3-18*k^2+360 = 0

82*k-4*k^3-18*k^2+360 = 0

2*(41*k-2*k^3-9*k^2+180) = 0

41*k-2*k^3-9*k^2+180 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 5, -5, 6, -6, 9, -9, 10, -10, 12, -12, 15, -15, 18, -18, 20, -20, 30, -30, 36, -36, 45, -45, 60, -60, 90, -90, 180, -180 }

1

k = 1

41*k-2*k^3-9*k^2+180 = 210

1

-1

k = -1

41*k-2*k^3-9*k^2+180 = 132

-1

2

k = 2

41*k-2*k^3-9*k^2+180 = 210

2

-2

k = -2

41*k-2*k^3-9*k^2+180 = 78

-2

3

k = 3

41*k-2*k^3-9*k^2+180 = 168

3

-3

k = -3

41*k-2*k^3-9*k^2+180 = 30

-3

4

k = 4

41*k-2*k^3-9*k^2+180 = 72

4

-4

k = -4

41*k-2*k^3-9*k^2+180 = 0

-4

k+4

45-2*k^2-k

41*k-2*k^3-9*k^2+180

k+4

2*k^3+8*k^2

41*k-k^2+180

k^2+4*k

45*k+180

-45*k-180

0

45-2*k^2-k = 0

DELTA = (-1)^2-(-2*4*45)

DELTA = 361

DELTA > 0

k = (361^(1/2)+1)/(-2*2) or k = (1-361^(1/2))/(-2*2)

k = -5 or k = 9/2

k in { -5, 9/2, -4}

2*(k+5)*(k-9/2)*(k+4) = 0

(2*(k+5)*(k-9/2)*(k+4))/(2*(2*k+8)*(k+4)) = 0

(2*(k+5)*(k-9/2)*(k+4))/(2*(2*k+8)*(k+4)) = 0 // * 2*(2*k+8)*(k+4)

2*(k+5)*(k-9/2)*(k+4) = 0

( k+4 )

k+4 = 0 // - 4

k = -4

( k+5 )

k+5 = 0 // - 5

k = -5

( k-9/2 )

k-9/2 = 0 // + 9/2

k = 9/2

k in { -4}

k in { -5, 9/2 }

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